-0.43x^2-0.19x+5=0

Solution for -0.43x^2-0.19x+5=0 equation:

-0.43x^2-0.19x+5=0

a = -0.43; b = -0.19; c = +5;
Δ = b2-4ac
Δ = -0.192-4·(-0.43)·5
Δ = 8.6361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.19)-\sqrt{8.6361}}{2*-0.43}=\frac{0.19-\sqrt{8.6361}}{-0.86}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.19)+\sqrt{8.6361}}{2*-0.43}=\frac{0.19+\sqrt{8.6361}}{-0.86}
$